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What steps will reproduce the problem?
1. set up a symlink pointing to a path outside user home directory as described
in issue 55 , e.g. a symlink called "foo" pointng to /tmp/foo
2. try to obtain access to that link (e.g. "CWD foo")
pyftpdlib will reply with:
550 "/" points to a path which is outside the user's root directory.
expected response should be:
550 "foo" points to a path which is outside the user's root directory.
From g.rodola on July 13, 2011 19:08:42
Original issue: http://code.google.com/p/pyftpdlib/issues/detail?id=180
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